php中输出json对象的值(实现方法)
author:一佰互联 2019-04-25   click:203

实例如下所示:

 <!DOCTYPE html><html><body><?php $json = "{"report":{"date":"2012-04-10","content":"abcdefght"}}"; $arr = (array) json_decode($json,true); echo "当前日期是:". $arr["report"]["date"];echo "<br/>";echo "<pre>"; print_r($arr);echo "</pre>";   foreach($arr as $arrvalue) { foreach($arrvalue as $key=>$value) {  echo "[$key] = $value <br />"; } }echo "<br/>";?> </body></html>

<!DOCTYPE html><html><body><?php$file_exists = file_exists("json.txt");if( $file_exists ){ $myfile = fopen("json.txt", "r") or die(""); $content = fread($myfile,filesize("json.txt")); fclose($myfile); echo $content; echo "<br/>"; $arr=(array)json_decode($content,true); echo $arr["CSS"]; echo "<br/>"; echo $arr["AJAX"];}?> </body></html>

json.txt:

{ "AJAX": "Asynchronous JavaScript and XML", "CSS": "Cascading Style Sheets"}

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