php实现头像上传预览功能
author:一佰互联 2019-04-26   click:209

本文实例为大家分享了php实现头像上传预览功能的具体代码,供大家参考,具体内容如下

主页面1.php

<html><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>上传头像</title><style type="text/css">  *{    font-family:"微软雅黑";}  #zong{    /*border:1px solid black;*/    position:relative;    width:52%;    height:500x;    left:24%}  .nr{    float:left;    margin-right:30px;}  #yl{width:240px; height:240px; background-size:240px 240px;}  #file{width:240px; height:240px; float:left; opacity:0;}</style></head><body><div id="zong"><form id="sc" action="2.php" method="post" enctype="multipart/form-data" target="shangchuan">    <input type="hidden" name="tp" value="" id="tp" />    <div id="yl" style="background-image:url(./image/1.jpg)" class="nr">//头像显示的位置    <input type="file" name="file" id="file" onchange="document.getElementById("sc").submit()" />  </div>  <div class="nr">  </div> </form><iframe style="display:none" name="shangchuan" id="shangchuan"></iframe></div></body><script type="text/javascript">//回调函数,调用该方法传一个文件路径,改变背景图function showimg(url){  var div = document.getElementById("yl");  div.style.backgroundImage = "url("+url+")";    document.getElementById("tp").value = url;}</script></html>

处理页面2.php

<?phpsession_start();$uid = $_SESSION["uid"];if($_FILES["file"]["error"]){  echo $_FILES["file"]["error"];}else{  if(($_FILES["file"]["type"]=="image/jpeg" || $_FILES["file"]["type"]=="image/png")&& $_FILES["file"]["size"]<1024000)  {    $fname = "./a/image/".date("YmdHis").$_FILES["file"]["name"];  //头像存储的路径        $filename = iconv("UTF-8","gb2312",$fname);        if(file_exists($filename))    {      echo "<script>alert("该文件已存在!");</script>";    }    else    {      move_uploaded_file($_FILES["file"]["tmp_name"],$filename);            unlink($_POST["tp"]);      echo "<script>parent.showimg("{$fname}");</script>";    }      }}

打开显示:

点击图片位置弹出选择框:

选择图片完成后:

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持网页设计。